先化简,再求职①x²-4x+4/x²-4-x+2/x-2 其中x=根号2②(x-1/3x-x+1/x)×x/x²-1 其中,x=2
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解:(x²-4x+4)/(x²-4)-(x+2)/(x-2)
=(x-2)²/(x-2)(x+2)-(x+2)/(x-2)
=(x-2)²-(x+2)²/(x+2)(x-2)
=(x²-4x+4-x²-4x-4)/(x+2)(x-2)
=-8x/(x²-4)
=-8√2/[(√2)²-4]
=4√2
[(x-1)/3x-(x+1)/x)]*x/(x²-1)
=[(x-1)/3x-(x+1)/x)]*x/(x-1)(x+1)
=[(x-1-3x-3)/3x]*x/(x-1)(x+1)
=[(-2x-4)/3x]*x/(x-1)(x+1)
=(-2x-4)/(3x²-3)
=(-2*2-4)/(3*2²-3)
=-8/9
=(x-2)²/(x-2)(x+2)-(x+2)/(x-2)
=(x-2)²-(x+2)²/(x+2)(x-2)
=(x²-4x+4-x²-4x-4)/(x+2)(x-2)
=-8x/(x²-4)
=-8√2/[(√2)²-4]
=4√2
[(x-1)/3x-(x+1)/x)]*x/(x²-1)
=[(x-1)/3x-(x+1)/x)]*x/(x-1)(x+1)
=[(x-1-3x-3)/3x]*x/(x-1)(x+1)
=[(-2x-4)/3x]*x/(x-1)(x+1)
=(-2x-4)/(3x²-3)
=(-2*2-4)/(3*2²-3)
=-8/9
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