Question

matlab求解四元二次方程~ 在线等解答！！！！

a*b/c=o.ooo903；
a*d/(1-c)=o.ooooo488；
(0.08-a)/(0.15-b)=4.245/c；
(0.08-a)/(0.02-d)=3.63/(1-c)；

Answer 1

[a,b,c,d]=solve('a*b/c=0.000903','a*d/(1-c)=0.00000488','(0.08-a)/(0.15-b)=4.245/c','(0.08-a)/(0.02-d)=3.63/(1-c)','a,b,c,d')

a =

0.0013130631537901804172323027371857
-0.63477816018628127667663815400259
0.085072718754670097655476561763924
-0.00095762172217900139607071049851584

b =

0.14606302109164088248065705542596
-0.0012780507936343243606698105797387
0.16902953857654129235710922483712
0.15309635783199948473254469070713

c =

0.21239199460322438321390635885196
0.89842605914486496567547206687129
15.924476629627638055670507408755
-0.16235702973024584170316845756211

d =

0.0029271456252822683985793670672084
-0.00000078087253541866820793611338927618
-0.00085610812747870203869203792551936
-0.0059233225121258441007501164050328 -0.0059233225121258441007501164050328

追问

怎么这么多数字，是有多组解么？a、b、c是四个解，为什么最后一个变量d又是五个解。。。 求大神解答。。