Question

if(++Time_Count != 50) return;中的return怎么理解？

/*************** writer:shopping.w ******************/
#include <reg52.h>
#define uint unsigned int
#define uchar unsigned char

sbit RED_A = P0^0;
sbit YELLOW_A = P0^1;
sbit GREEN_A = P0^2;
sbit RED_B = P0^3;
sbit YELLOW_B = P0^4;
sbit GREEN_B = P0^5;

uchar Time_Count = 0,Flash_Count = 0,Operation_Type = 1;

void T0_INT() interrupt 1
{
TMOD = 0x01;
IE = 0x82;
TR0 = 1;
TH0 = (60000-50000)/256;
TL0 = (60000-50000)%256;

switch(Operation_Type)
{
case 1:
RED_A=0;YELLOW_A=0;GREEN_A=1;
RED_B=1;YELLOW_B=0;GREEN_B=0;
if(++Time_Count != 50) return;
Time_Count=0;
Operation_Type = 2;
break;
case 2:
if(++Time_Count != 8) return;
Time_Count=0;
YELLOW_A=!YELLOW_A;
GREEN_A=0;
if(++Flash_Count != 10) return;//黄灯闪烁5次
Flash_Count=0;
Operation_Type = 3;
break;
case 3:
RED_A=1;YELLOW_A=0;GREEN_A=0;
RED_B=0;YELLOW_B=0;GREEN_B=1;
if(++Time_Count != 20) return;
Time_Count=0;
Operation_Type = 4;
break;
case 4:
if(++Time_Count != 8) return;
Time_Count=0;
YELLOW_B=!YELLOW_B;
GREEN_B=0;
if(++Flash_Count !=10)
return;
Flash_Count=0;
Operation_Type = 1;
break;
}
}

void main()
{
TMOD = 0x01;
IE = 0x82;
TR0 = 1;
TH0 = (60000-50000)/256;
TL0 = (60000-50000)%256;
RED_A=0;YELLOW_A=0;GREEN_A=1;
RED_B=1;YELLOW_B=0;GREEN_B=0;
while(1);

}

Answer 1

if(++Time_Count != 50) return;

ruturn指的是返回以下这个循环体：
void T0_INT() interrupt 1
{
TMOD = 0x01;
IE = 0x82;
TR0 = 1;
TH0 = (60000-50000)/256;
TL0 = (60000-50000)%256;

switch(Operation_Type)
{

追问

case 2:
if(++Time_Count != 8) return;
Time_Count=0;
YELLOW_A=!YELLOW_A;
GREEN_A=0;
if(++Flash_Count != 10) return;//黄灯闪烁5次
Flash_Count=0;

这段程序怎么理解呢？大神求详解，你现在的解答我已经明白了许多了，整段好像我还是不是很理解，麻烦了哦

Answer 2

Time_Count是一个计数器，当Time_Count += 1后，判断Time_Count是否为50，如果不等，就退出函数T0_INT()，直到调用T0_INT()函数使Time_Count加1后是50了，该函数才得以运行下面代码。

Answer 3

如果Time_Count增1计数不到50的话，就退出函数返回到主调函数！

Answer 4

条件语句，若等于五十则顺序执行，若不等于五十则返回主函数，然后到中断，一直循环判断

Answer 5

return 是函数运行返回值，执行return后， return 下面的语句是不执行的。