Question

asp.net 随机生成数字串

string DateInfo = DateTime.Now.ToString("yyyyMMddHHmmssfff");
我用这句获取的是当前时间 我想获取成我想要的 格式 比如 201362****_0

****是随机生成的四位数字 该怎么调用啊?

Answer 1

 public static string YZM()
    {
        string[] rander = {"p","0","1","2","3","4","5","6","7","8","9","a","s","d","f","g","h","j","k","l","q","w","e","r","t","y","u","i","o","z","x","v","c","b","n","m","Q","W","E","R","T","Y","U","I","O","P","A","S","D","F","G","H","J","K","L","Z","X","C","V","B","N","M"};
        int sub;
        string yzm = ""; 
        Random rand = new Random();
        rand = new Random(345 * unchecked((int)DateTime.Now.Second));
        for (int i = 0; i < 4; i++)
        {
            
            sub = rand.Next(61);
              yzm += rander[sub];

        }
        return yzm;

    }

纯数字还是要字母，纯数字，把那个数组改一下就行了，然后把你前边的字串拼接就行了

Answer 2

Random r=new Random();
stringDateInfo=DateTime.Now.ToString("yyyyMd")+r.Next(1000-10000).ToString()+"_0"

大致是这样，我没有运行，你稍微修改一下就可以了

Answer 3

使用随机数生成一个4位的数字就可以了，再在前面加上你的日期。