Question

java编程题，写一个point类，计算两个point实例间的距离

急

Answer 1

Point类Point.java
public class Point {

public Point(){}

public Point(double x, double y) {

super();

this.x = x;

this.y = y;

}

public double getX() {
return x;
}

public void setX(double x) {
this.x = x;
}

public double getY() {
return y;
}

public void setY(double y) {
this.y = y;
}

private double x = 0;

private double y = 0;

public double getDistance(Point p){

double x = p.getX() - this.x;

double y = p.getY() - this.y;

return Math.sqrt(x*x + y*y);

}

}

测试类Test.java
public class Test {

public static void main(String[] args){

Point p1 = new Point(0,0);

Point p2 = new Point(100, 0);

System.out.print(p1.getDistance(p2));

}

}

Answer 2

太简单了吧，定义属性x，y
声明对象
距离(x1-x2)*(x1-x2)+(y1-y2)*(y1-y2)开根号

Answer 3

	public class Point {
		public double x;
		public double y;

		public Point(double x, double y) {
			this.x = x;
			this.y = y;
		}

		public double distance(Point pt) {
			double px = pt.x - this.x;
			double py = pt.y - this.y;
			return Math.sqrt(px * px + py * py);
		}
	}

Answer 4

double x = p1.getX() - p2.getX();
double y = p1.getY() - p2.getY();
return Math.sqrt(x*x+y*y);