Question

C语言0错误 0警告但是debug error.

#include <stdio.h>
int main()
{
int n,i,sum,de,nu,mid;
printf("please enter number: ");
scanf("%f",&n);
if (n<=0)
printf("error\n");
else
{
for(i=1,sum=0,de=1,nu=1;i<=n;i++)

sum=sum+de/nu;
mid=de;
de=de+nu;
nu=mid;

printf("n=%.0f,sum=%f\n",n,sum);
}
}求大神给答案

Answer 1

#include <stdio.h>
int main()
{
 int n,i,de,nu,mid;
 float sum;    //sum定义成float
 printf("please enter number: ");
    scanf("%d",&n);    //输入整型用%d
 if (n<=0)
       printf("error\n");
 else
 {
  for(i=1,sum=0,de=1,nu=1;i<=n;i++)
    {
   sum=sum+de/nu;    //这四句应该用{}括起来
   mid=de;
   de=de+nu;
   nu=mid;
    }
  printf("n=%d,sum=%f\n",n,sum);    //输出整型用%d
    }
}

Answer 2

#include <stdio.h>
int main()
{
int n,i,sum,de,nu,mid;
printf("please enter number: ");
scanf("%d",&n);//==============这里
if (n<=0)
printf("error\n");
else
{
for(i=1,sum=0,de=1,nu=1;i<=n;i++)

sum=sum+de/nu;
mid=de;
de=de+nu;
nu=mid;
printf("n=%d,sum=%d\n",n,sum);//==========这里
}
}

希望回答能帮到你，哪里不清楚再问。

Answer 3

1.  n等变量均改为float

2. for循环里，四句代码应该用{}，否则只会循环执行sum=sum+de/nu;这一句

   for(i=1,sum=0,de=1,nu=1;i<=n;i++)
   { 
     sum=sum+de/nu;
     mid=de;
     de=de+nu;
     nu=mid;

   }

Answer 4

数据定义格式不对，你定以为整数，输入类型为浮点数，应将类型改为float

#include <stdio.h>
int main()
{
float n,i, sum,de,nu,mid;
printf("please enter number: ");
scanf("%f",&n);
if (n<=0)
printf("error\n");
else {
for(i=1,sum=0,de=1,nu=1;i<=n;i++)
sum=sum+de/nu;
mid=de;
de=de+nu;
nu=mid;
printf("n=%.0f,sum=%f\n",n,sum);
}
}

Answer 5

很简单，把scanf("%f",&n);改成scanf("%d",&n);
把printf("n=%.0f,sum=%f\n",n,sum);改成printf("n=%.0d,sum=%d\n",n,sum);
我在c++上试过了，没错的。