
高等数学,求不定积分
1个回答
展开全部
令 x = asint,则
I = ∫acostdt/[a^3(cost)^3]
= (1/a^2)∫(sect)^2dt
= (1/a^2)tant + C
= x/[a^2√(a^2-x^2)] + C
I = ∫acostdt/[a^3(cost)^3]
= (1/a^2)∫(sect)^2dt
= (1/a^2)tant + C
= x/[a^2√(a^2-x^2)] + C
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询