Question

用java编写输出满足1+2+3+....+n<8888的最大正整数n

Answer 1

int sun = 0;
for(int i=1;i>0;i++)
{

sun = sun+i;
if(sun>8888)
{
System.out.println(sun);
System.out.println(i-1);

break;
}8911
132

Answer 2

int nSum = 0;
int i = 1;
do{
nSum += i;
if( nSum + (i + 1) >= 8888 ){
break;
}
i++;
}while( true ); System.out.println(i);

Answer 3

int result = 0;
for (int i = 1; i < 8888; i++) {
result += i;
}
System.out.println("结果为:"+result);