若|a-2|+（b+3）的二次方=0 求3a的二次方b-{2ab的二次方-2（ab-1.5a二次方b）}+3ab二次方的值
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a-2|+(b+3)�0�5=0 两个非负数的和为0,则他们都等于0
a-2=0 b+3=0 解得
a=2 b=-3
3a�0�5b-[2ab�0�5-2(ab-1.5a�0�5b)+ab]+3ab�0�5
=3a�0�5b-(2ab�0�5-2ab+3a�0�5b+ab)+3ab�0�5
=3a�0�5b-(2ab�0�5-ab+3a�0�5b)+3ab�0�5
=3a�0�5b-2ab�0�5+ab-3a�0�5b+3ab�0�5
=ab�0�5+ab
=ab(b+1)
=2×(-3)×(-3+1)
=12
a-2=0 b+3=0 解得
a=2 b=-3
3a�0�5b-[2ab�0�5-2(ab-1.5a�0�5b)+ab]+3ab�0�5
=3a�0�5b-(2ab�0�5-2ab+3a�0�5b+ab)+3ab�0�5
=3a�0�5b-(2ab�0�5-ab+3a�0�5b)+3ab�0�5
=3a�0�5b-2ab�0�5+ab-3a�0�5b+3ab�0�5
=ab�0�5+ab
=ab(b+1)
=2×(-3)×(-3+1)
=12
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