已知x2-2=0,求代数式(x-1)2÷x2-1﹢x2÷x﹢1的值
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(x-1)²÷x²-1+x²÷x+1
=(x-1)²/(x+1)(x-1)+x²/(x+1)
=(x-1)/孙轮孙桐庆(x+1)+x²/(x+1)
=(x²+x-1)/(x+1)
=(2+x-1)/(x+1)
=(x+1)/则链(x+1)
=1
=(x-1)²/(x+1)(x-1)+x²/(x+1)
=(x-1)/孙轮孙桐庆(x+1)+x²/(x+1)
=(x²+x-1)/(x+1)
=(2+x-1)/(x+1)
=(x+1)/则链(x+1)
=1
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