Question

这道题怎么求导

Answer 1

母方分之分导减母导

Answer 2

|nf(x)=InIn(1/x)-2lnx
f'(x)/f(x)=-1/[xIn(1/x)]-2/x
f'(x)=-f(x){1/[xIn(1/x)]-2/x}
f'(x)=lnx/x²×{1/[xIn(1/x)]-2/x}
f'(x)=-1/x³-2lnx/x³