Question

Python如何实现找出嵌套字典中内部字典中的键

比如{'assd': {'a': 1, 'c': 1, 'b': 1}, '5545': {'a': 5, 'e': 5, 'd': 1}}如何返回（'a','b','c','d',e')

若以下回答无法解决问题，邀请你更新回答

Answer 1

递归。用这个函数把dict里面的所有value用递归的方法提取到一个空list里面12345678910111213def dict2flatlist(d,l): print(d) for x in d.keys(): if type(d[x]) == dict: dict2flatlist(d[x],l) else: l.append(d[x]) d = {1:"a",2:"b",3:{4:"c",5:"d",6:{7:"e"}},8:"f"} l = []dict2flatlist(d,l)print(l)希望对你有帮助

Answer 2

def dict2flatlist(d,l):

print(d)

for x in d.keys():

if type(d[x])==dict:

dict2flatlist(d[x],l)

else:

l.append(d[x])

d = {1:"a",2:"b",3:{4:"c",5:"d",6:{7:"e"}},8:"f"} 

l = []

dict2flatlist(d,l)

print(l)

感谢   cn#aGakaaupBV