Question

(X/4)²+((40-x)/4)²=58 求解

如题，需要详细过程。。。。

Answer 1

(X/4)(X/4)+((40一X)/4)(40一X)/4)=58
ⅩX/16+100一5X+XX/16=58
XX/8一5X+42=0
XX一40X十336=0
(X一12)(X一28)=0
X一12=0
X1=12
X一28=0
X2=28'

Answer 2

解:(X/4)²+(10-X/4)²=58
X²/16+100-5X+X²/16=58
X²/8-5X+42=0
X²-40X+336=0
X=(40±√(1600-1344))/2=(40±16)/2
X1=28
X2=12

Answer 3

(x/4)²+((40-x)/4)²=58
x²/16+(1600-80x+x²)/16=58
x²+1600-80x+x²=928
2x²-80x+672=0
x²-40x+336=0
(x-28)(x-12)=0

x1=28
x2=12

Answer 4

(X/4)²+（10-(X/4)）²=58
(X/4)²+100+(X/4)²-2*10*(X/4)=58
X²/8-5X+42=0
b^2-4ac=2
x=[-b±(b^2-4ac)^(1/2)]/2a=12或28

Answer 5

解：
整理，得x²-40x+336=0
(x-12)(x-28)=0
x=12或x=28