Question

求解，高中化学方程式

Answer 1

CH3CHO+O2====CH3COOHCH3CHO+H2====CH3CH2O2CH3CH2CH2OH+O2==Cu/Ag==2CH3CH2CHO+2H2O2CH3OH+O2==Ag/Cu==2CH2O+2H2O2CH3OH+2NA====2CH3ONa+H2CH2=CH2+H2O==(一定条件)==CH3CH2OHCH3COOH+CH3OH==(浓H2SO4，加热，可逆)==CH3COOCH3+H2OCH3COOH+CH3CH2CH2OH==(浓H2SO4，加热，可逆)==CH3COOCH2CH2CH3+H2OCH3COOH+CH3-CHOH-CH3==(浓H2SO4，加热，可逆)==CH3COOCH(CH3)CH3+H2OCH2OOH+CH3OH==(浓H2SO4，加热，可逆)==CH2OOCH3+H2OCH2OOH+CH3CH2OH==(浓H2SO4，加热，可逆)==CH2OOCH2CH3+H2OCH2OOH+CH3CHOHCH3==(浓H2SO4，加热，可逆)==CH2OOCH(CH3)CH3+H2OCH3CH2COOH+CH3OH==(浓H2SO4，加热，可逆)==CH3CH2COOCH3+H2OCH3CH2COOH+CH3CH2OH==(浓H2SO4，加热，可逆)==CH3CH2COOCH2CH3+H2OCH3COOH+CH3CH2CH2OH==(浓H2SO4，加热，可逆)==CH3COOCH2CH2CH3+H2O（你们老师有病没有，出这种题）O-O-H||CH3O2；H-C-H；CH2OOHHHO-O-H||||CH3H6O2；H-C-C-C-HCH3CH2COOH||HHCH3CH2COOCH2CH2CH3+H2O==(碱性条件，加热)==CH3CH2COOH+CH3CH2CH2OH(C6H5)-COOCH2CH3==(碱性条件，加热)==(C6H5)-COOH+CH3CH2OH累死老夫了，要不是我心情好，我才不跟你写==

Answer 2

这应该是生产硝化甘油的方程。

Answer 3

这是酯化反应

Answer 4

甘油的硝化反应，还需加热