求解下题不定积分问题
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原式=1/2*∫(x²-5x+7)dsin2x
=1/2*(x²-5x+7)sin2x-1/2*∫sin2xd(x²-5x+7)
=1/2*(x²-5x+7)sin2x-1/2*∫(2x-5)sin2xdx
=1/2*(x²-5x+7)sin2x+1/4*∫(2x-5)dcos2x
=1/2*(x²-5x+7)sin2x+1/4*(2x-5)cos2x-1/4*∫cos2xd(2x-5)
=1/2*(x²-5x+7)sin2x+1/4*(2x-5)cos2x-1/4*∫2cos2xdx
=1/2*(x²-5x+7)sin2x+1/4*(2x-5)cos2x-1/4*sin2x+C
=1/4*(2x²-10x+13)sin2x+1/4*(2x-5)cos2x+C
=1/2*(x²-5x+7)sin2x-1/2*∫sin2xd(x²-5x+7)
=1/2*(x²-5x+7)sin2x-1/2*∫(2x-5)sin2xdx
=1/2*(x²-5x+7)sin2x+1/4*∫(2x-5)dcos2x
=1/2*(x²-5x+7)sin2x+1/4*(2x-5)cos2x-1/4*∫cos2xd(2x-5)
=1/2*(x²-5x+7)sin2x+1/4*(2x-5)cos2x-1/4*∫2cos2xdx
=1/2*(x²-5x+7)sin2x+1/4*(2x-5)cos2x-1/4*sin2x+C
=1/4*(2x²-10x+13)sin2x+1/4*(2x-5)cos2x+C
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