Question

用MATLAB作出柱面x^2+y^2=4 和柱面x^2+z^2=4 相交的图形.

Answer 1

程序如下：

t=0:pi/20:2*pi;
x=sin(t)*2;
y=cos(t)*2;
z=linspace(-5,5,length(t));
X=meshgrid(x);Y=meshgrid(y);Z=[meshgrid(z)]';
mesh(X,Y,Z)%第一个圆柱面
xlabel('x')
ylabel('y')
zlabel('z')
hold on
x1=sin(t)*2;
z1=cos(t)*2;
y1=linspace(-5,5,length(t));
X1=meshgrid(x1);Y1=[meshgrid(y1)]';Z1=meshgrid(z1);
mesh(X1,Y1,Z1)%第二个圆柱面
plot3(sin(t)*2,cos(t)*2,cos(t)*2,'k-*','LineWidth',2)%交线1
hold on
plot3(-sin(t)*2,-cos(t)*2,cos(t)*2,'k-*','LineWidth',2)%交线2
title('柱面x^2+y^2=4 和柱面x^2+z^2=4 相交的图形')

结果：