Question

用洛必达法则求limx→0x^x的极限

Answer 1

简单计算一下即可，答案如图所示

Answer 2

(x→0)lim(x^x) = e^(x→0)ln(x^x)
= e^(x→0)lim[xlnx]
= e^(x→0)lim{(lnx)/(1/x)}
罗比塔
= e^(x→0)lim{(1/x)/(-1/x²}
= e^(x→0)lim(-x)
= e^0
= 1