求此不定积分
展开全部
=1/4∫x^8/(x^4+1)(x^4+2)dx^4
=1/4∫u²/(u+1)(u+2)du
=1/4∫u²/(u+1)-u²/(u+2)du
=1/4∫u-1+1/(u+1)-(u-2+4/(u+2))du
=(1/4)(u+ln(u+1)-4ln(u+2))+C
=x^4/4+ln(x^4+1)/4-ln(x^4+2)+C
=1/4∫u²/(u+1)(u+2)du
=1/4∫u²/(u+1)-u²/(u+2)du
=1/4∫u-1+1/(u+1)-(u-2+4/(u+2))du
=(1/4)(u+ln(u+1)-4ln(u+2))+C
=x^4/4+ln(x^4+1)/4-ln(x^4+2)+C
本回答被网友采纳
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询