设二重积分的积分区域D是4≤x^2+y^2≤9则∫∫dxdy=
1个回答
展开全部
4 ≤ x² + y² ≤ 9
==> 4 ≤ r² ≤ 9
==> 2 ≤ r ≤ 3
∫∫D dxdy = D的面积 = π * 3² - π * 2² = 5π
或极坐标的∫∫D dxdy = ∫(0,2π) dθ ∫(2,3) r dr
= [ θ ]:(0,2π) * [ (1/2)r² ]:(2,3)
= 2π * (1/2)(9 - 4) = 5π
==> 4 ≤ r² ≤ 9
==> 2 ≤ r ≤ 3
∫∫D dxdy = D的面积 = π * 3² - π * 2² = 5π
或极坐标的∫∫D dxdy = ∫(0,2π) dθ ∫(2,3) r dr
= [ θ ]:(0,2π) * [ (1/2)r² ]:(2,3)
= 2π * (1/2)(9 - 4) = 5π
本回答被提问者采纳
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询