如图,已知∠ACB=∠ADE,∠ABC=∠AED.求证:∠ABE=∠ACD
http://b203.photo.store.qq.com/http_imgload.cgi?/rurl4_b=671ad62e40a3a26a97aa9fef0d3d...
http://b203.photo.store.qq.com/http_imgload.cgi?/rurl4_b=671ad62e40a3a26a97aa9fef0d3dc1c386d99adde3ad5ade5508af387e546881f184d2116540e22c597280070d7fd82e8d8c23ba63cab10a8a4acbd39d9113a7e94ab5f26644fd65a8954a83eb23042973ef05ce&a=203&b=203(图片链接)
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2013-06-16
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由已知条件得。△ABC相似△AED∴AB:AE=AC:AD且∠BAC=∠EAD ∴∠BAE=∠CAD∴△ABE相似△ACD∴∠ABE=∠ACD
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