Question

extjs实现formPanel问题

想实现的功能是左边树形菜单点击之后弹出一个窗口，但是老是报
TypeError: comp is undefined这个错误，太坑爹了

function databaseInfoFn(){
var dbForm = new Ext.FormPanel({
id:"dbForm",
width:340,
height:130,
frame:true,
labelAlign:"right",
monitorValid:true,
items:[],
buttons:[]
});
var dbWindow = new Ext.Window({
width:340,
height:180,
title:"给角色分配权限",
items:dbForm,
autoScroll:true,
resizable:true,
draggable:true,
closable:true
});
dbWindow.show();

if (!databaseInfoFnPageIsOpen) {
var tabPage = tabPanel.add({
title : "数据库管理",
height : 400,
closable : true,
layout : "fit",
items : [ dbForm ],
listeners : {
beforedestroy : function() {
databaseInfoFnPageIsOpen = false;
}
}
});
tabPanel.setActiveTab(tabPage);
databaseInfoFnPageIsOpen = true;
}
}
如下的代码删掉，还是一样的错，故与下面的代码无关
if (!databaseInfoFnPageIsOpen) {
var tabPage = tabPanel.add({
title : "数据库管理",
height : 400,
closable : true,
layout : "fit",
items : [ dbForm ],
listeners : {
beforedestroy : function() {
databaseInfoFnPageIsOpen = false;
}
}
});
tabPanel.setActiveTab(tabPage);
databaseInfoFnPageIsOpen = true;
}

Answer 1

comp 哪呢？

追问

我也不知道从什么地方跑出来个comp

追答

用firebug瞅瞅是哪行？