1个回答
展开全部
(xy-x的2次方)除以xy分之（x的2次方-2xy+y的2次方）成x的2次方分之(x-y)?
=(xy-x的2次方)/[(x的2次方-2xy+y的2次方)/(xy)]*[(x-y)/x²]
=-x(x-y)/[(x-y)²/(xy)]*[(x-y)/x²]
=-x(x-y)*xy*(x-y)/[(x-y)²x²]
=-(x-y)²x²y/[(x-y)²x²]
=-y
=-1/3
=(xy-x的2次方)/[(x的2次方-2xy+y的2次方)/(xy)]*[(x-y)/x²]
=-x(x-y)/[(x-y)²/(xy)]*[(x-y)/x²]
=-x(x-y)*xy*(x-y)/[(x-y)²x²]
=-(x-y)²x²y/[(x-y)²x²]
=-y
=-1/3
本回答由提问者推荐
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
