Question

输入一个时间数值，再输入秒数 n，输出该时间再过 n 秒后的时间值，时间的表示形式为时:分:秒，

#include <stdio.h>struct time{ int hour, minute, second;};void timecal(struct time *p, int n);
int main(void){ int n; int repeat, ri; struct time time;
scanf("%d", &repeat); for(ri = 1; ri <= repeat; ri++){ scanf("%d:%d:%d", &time.hour, &time.minute, &time.second); scanf("%d",&n); timecal(&time,n); printf("time: %d:%d:%d\n", time.hour, time.minute, time.second);}
void timecal(stuct time*p, int n);{ if(time.second+n<60)time.second+=n; else if(time.second+n==60){ time.second=0; time.minute++; if(time.minute==60){ time.minute=0; time.hour++; if(time.hour==24) time.hour=0; } } else{ time.second=(n+time.second)%60; if((time.minute+(time.second+n)/60)<60) time.minute+=(time.second+n)/60; else if((time.minute+(time.second+n)/60)==60){ time.minute=0; time.hour++; if(time.hour==24) time.hour=0; } else{ time.minute=(time.minute+(time.second+n)/60)%60; if((time.hour+(time.minute+(time.second+n)/60)/60)<24）time.hour=0; else time.hour=(time.hour+(time.minute+(time.second+n)/60)/60)%24; } } }
程序有点问题，求修正，另外有木有大神有更简单的程序分享

Answer 1

#include <stdio.h>
struct time{
    int hour, minute, second;
};
void timecal(struct time *p, int n)
{
	p->second += n;
	if (p->second>=60)
	{
		p->minute += p->second/60;//60s一分钟
		p->second %= 60;//余数为当前秒数		
	}
	if(p->minute>=60)
	{
		p->hour += p->minute/60;//60分一小时
		p->minute %=60;//余数为当前分钟数
	}
	if (p->hour>=24)
	{
		p->hour %= 24;//余数为当前小时
	}
}
int main(void)
{
    int n;
    int repeat, ri;
    struct time time;
    scanf("%d", &repeat);
    for(ri = 1; ri <= repeat; ri++){
        scanf("%d%d%d", &time.hour, &time.minute, &time.second);
        scanf("%d",&n);
        timecal(&time,n);
        printf("time: %d:%d:%d\n", time.hour, time.minute, time.second);
	}
		
	return 0;
} 
//测试无误