Question

java编程问题，急急急！随机产生并输出N个随机数，直到最近产生两个数之和为100。

随机产生并输出N个随机数，直到最近产生两个数之和为100。

Answer 1

    Random random = new Random();
    int i,j;
    while(true){
    i = random.nextInt(100);
    j = random.nextInt(100);
    if(i+j==100){
    System.out.print("i:"+i+"  j:"+j);
    break;
    }
    }

简单啊，取两个随机数判断下就ok

Answer 2

package test;

public class TestRandom {

public static void main(String[] args) {
int x = (int)(Math.random()*100);
int y = (int)(Math.random()*100);
while(x+y!=100){
System.out.println(x);
x = y;
y=(int)(Math.random()*100);

}
System.out.println(x);
System.out.println(y);
}
}

Answer 3

死循环里套两个随机数，和为100就跳出循坏

Answer 4

import java.util.Random;
public class RandomADD {
public static void main(String[] args){
int last=-1;
int now=0;
Random rd=new Random();
int range=100;//随机数范围0~90
boolean run=true;

while(run){
now=rd.nextInt(range);
if(last==-1){
last=now;
System.out.println("本次随机数为:"+now);
}else{
if((last+now)==100){
run=false;
System.out.println("本次随机数为:"+now+" 上次随机数为："+last+" 和为："+(last+now));
}else{

System.out.println("本次随机数为:"+now+" 上次随机数为："+last+" 和为："+(last+now));
last=now;
}
}
}
}
}