Question

【在线等】c语言程序：对n的阶乘求和，n=1到10

Answer 1

#include <stdio.h>

double fun(int n)
{
double result = 1.0;
if (n == 0)
return 1.0;
while (n > 1)
result *= n--;
return result;
}

int main()
{
printf("\n10! =%lf\n\n", fun(10));
}
祝你愉快！

Answer 2

#include <stdio.h>
int main()
{
int a,b,c,n;
int sum=0;
scanf("%d",&n);
for(a=1;a<=n;a++)//控制1－10个数字
{
for(b=1,c=1;b<=a;b++)//控制每个数的阶乘
{
c=b*c;
}
sum+=c;//把结果累加在sum中
}
printf("%d",sum);
return 0;
}

Answer 3

Answer 4

#include"stdio.h"
int main()
{
int i, j, n, sum;
sum = 0;
for (i = 1; i <= 10; i++)
{
j = i;
n = 1;
while (j >= 1)
{
n *= j;
j--;
}
sum += n;
}
printf("1!+2!+3!+...+8!=%d\n",sum);
return 0;
}