1个回答
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A、氧原子含有8个质子,基态原子电子排布式为1S2 2S22P4,结构示意图为https://iknow-pic.cdn.bcebos.com/2f738bd4b31c87011f1fd551247f9e2f0608ffd8?x-bce-process=image/quality,q_85,故A错误;
B、氧离子含有8个质子,原子核外电子数为8+2=10,电子排布式为1S2 2S22P6,https://iknow-pic.cdn.bcebos.com/b21c8701a18b87d6e7ebcca8040828381e30fdd8?x-bce-process=image/quality,q_85为O2-的结构示意图,故B正确;
C、https://iknow-pic.cdn.bcebos.com/29381f30e924b8996e951e8f6d061d950b7bf6d8?x-bce-process=image/quality,q_85为S的原子结构示意图,故C错误;
D、https://iknow-pic.cdn.bcebos.com/cc11728b4710b912bb889149c0fdfc039245223f?x-bce-process=image/quality,q_85为Na的原子结构示意图,故D错误;
故选B.
B、氧离子含有8个质子,原子核外电子数为8+2=10,电子排布式为1S2 2S22P6,https://iknow-pic.cdn.bcebos.com/b21c8701a18b87d6e7ebcca8040828381e30fdd8?x-bce-process=image/quality,q_85为O2-的结构示意图,故B正确;
C、https://iknow-pic.cdn.bcebos.com/29381f30e924b8996e951e8f6d061d950b7bf6d8?x-bce-process=image/quality,q_85为S的原子结构示意图,故C错误;
D、https://iknow-pic.cdn.bcebos.com/cc11728b4710b912bb889149c0fdfc039245223f?x-bce-process=image/quality,q_85为Na的原子结构示意图,故D错误;
故选B.
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