Question

求大神帮我分析解答一下，谢谢了

Answer 1

#include <math.h>
float f(float x)
{return x*x+x-sqrt(x);
}
main()
{int i=0,x,min;
float a[10];
for(x=-5;x<=4;x++)
a[i++]=f(x);
min=0;
for(i=1;i<10;i++)
if(a[i]<a[min])
min=i;
printf("min=a[%d]=%f\n",min,a[min]);
getch();
}

Answer 2

第一题:
#include<stdio.h>

int main(void)
{
int num = 10,i;
float wage[10], nwage[10], sum = 0.0, nsum = 0.0;
for (i = 0; i < 10; ++i)
{
printf("请输入第%d位员工的工资: ",i+1);
scanf("%f",&wage[i]);
}
for (i = 0; i < 10; ++i)
{
if (wage[i] < 3000)
nwage[i] = wage[i] * 1.1;
else if (wage[i] <= 5000 || wage[i] >= 3000)
nwage[i] = wage[i] * 8.0 / 100 + wage[i];
else
nwage[i] = wage[i] * 6.0 / 100 + wage[i];
sum = sum + wage[i];
nsum = nsum + nwage[i];
}
printf("现工资\t\t\t新工资\n");
for (i = 0; i < 10; ++i)
{
printf("%6.2f\t\t\t%6.2f\n",wage[i],nwage[i]);
}
printf("全体员工所增加的工资总数为%6.2f\n", nsum - sum);
printf("公司所发的工资总数为: %6.2f\n",nsum);
return 0;
}
第二题:根号里面不能是负数...