Question

lua怎样将表tabB中的值赋给表tabA值

local tabA = {name = "ceshi" , age = 0, areg = "北京市"}
local tabB = {"wangjiajun", 32, "深圳市"}

最后变成{name = "wangjiajun" , age = 32, areg = "深圳市"}这样

Answer 1

tabA.name = tabB[1];
tabA.age = tabB[2];
tabA.areg= tabB[3];

追问

tabA = {{name = "ceshi" , age = 0, areg = "北京市"},{name1 = "aaaa" , age1 = 0, areg1 = "深圳市"}}
tabB = {"lishi",23,"深圳市","wangwu",40,"上海市"}

追答

tabA[[1].name = tabB[1];
tabA[1].age = tabB[2];
tabA[1].areg= tabB[3];
tabA[2].name = tabB[4];
tabA[2].age = tabB[5];
tabA[2].areg= tabB[6];

追问

是可变的呢？我不知道tabB有多少条这样的数据。格式是一定的。怎么循环去加载

追答

for i=0,#tabB-1, 3 do
tabA[i/3+1] = {}
tabA[i/3+1].name = tabB[i+1]
tabA[i/3+1].age = tabB[i+2]
tabA[i/3+1].areg = tabB[i+3]
end