Question

帮我计算，列式乘除号用中文代表就行了，不要理由，不算数不加分，回答时一定要详细

一。用简便方法计算 16/3-5/11-1/3 824-396 1.25x2.5x8x12 3884-299 4.05-2.83-1.17 (51+34/35)x17 698x11 19.95x72+28x19.95 二。巧算 38x1/4+17x0.25+45x25% 2.78x7.8+2.78x3.2-2.78 27x3.4+15.4x34-8.1x34 5/7x7÷5/7x7+1.01x99 666x9+46x111 2004x2002/2003 三。列式。被除数除以除数的商是9，余数是6，并且被除数，除数和余数的和是111，被除数和除数各是多少？

Answer 1

一。用简便方法计算
16/3-5/11-1/3
=(16/3-1/3)-5/11
=5-5/11
=4又6/11
824-396
=824-400+4
=424+4
=428
1.25x2.5x8x12
=(1.25x8)x(2.5x4x3)
=10x10x3
=300
3884-299
=3884-300+1
=3584+1
=3585
4.05-2.83-1.17
=4.05-(2.83+1.17 )
=4.05-4
=0.05
(51+34/35)x17
=(50+2-1/35)X17
=50X17+2x17-17/35
=850+34-17/35
=883又18/35
698x11
=(700-2)x11
=700x11-2x11
=7700-22
=7678
19.95x72+28x19.95
=19.95x(72+28)
=19.95x100
=1995
二。巧算
38x1/4+17x0.25+45x25%
=38x0.25+17x0.25+45x0.2 5
=0.25x(38+17+45)
=0.25x100
=25
2.78x7.8+2.78x3.2-2.78
=2.78x(7.8+3.2-1)
=2.78x10
=27.8
27x3.4+15.4x34-8.1x34
=2.7x34+15.4x34-8.1x34
=34x(2.7+15.4-8.1)
=34x10
=340
5/7x7÷5/7x7+1.01x99
=(5/7÷5/7)x7x7+1.01x100-1.01x1
=49+101-1.01
=150-1.01
=148.99
666x9+46x111
=111(6x9+46)
=111x(54+46)
=111x100
=11100
2004x2002/2003
=(2003+1)(2003-1)/2003
=(2003平方-1)/2003
=2003-1/2003
=2002又2002/2003
三。列式。被除数除以除数的商是9，余数是6，并且被除数，除数和余数的和是111，被除数和除数各是多少？
设除数是x
9x+6+x+6=111
x=9.9
9x9.9+6=95.1
被除数95.1,除数是9.9

Answer 2

(1)16/3-5/11-1/3=16/3-1/3-5/11=5-5/11=50/11
824-396 =824-400+4=424+4=428
1.25x2.5x8x12 =1.25X8X(2.5X4)X3=10X10X3=300
3884-299 =3884-300+1=3585
4.05-2.83-1.17 =4.05-(2.83+1.17)=4.05-4=0.05
(51+34/35)x17 =(51+1-1/35)X17=52X17-17/35=884-17/35=883又18/35
698X11=(700-2)X11=7700-22=7678
19.95x72+28x19.95 =19.95X(72+28)=1995
(2)38x1/4+17x0.25+45x25%=(38+17+45)X0.25=25
2.78x7.8+2.78x3.2-2.78=(7.8+3.2-1)X2.78=27.8
27x3.4+15.4x34-8.1x34 =(2.7+15.4-8.1)X34=340
5/7X7÷5/7x7+1.01x99 =5÷5+(100-1)X1.01=101+1-1.01=100.99
666x9+46x111 =111X(6X9+46)=11100
2004x2002/2003 =(2003+1)X(2003-1)/2003=2003-1/2003=2002又2002/2003
(3)被除数÷除数=商+余数 则被除数=除数X商+余数 被除数=除数X9+6
被除数+除数+余数=111 则被除数+除数=105
所以 除数X9+6+除数=105 则 除数=9.9 被除数=95.1