Question

python程序设计s=1+1/2+1/3+....+1/n,求与八最接近的s的值与其对应的n值。

Answer 1

所以n是1673 ，s是7.999888

首先定义了一个初始最小差值 min_diff，以及对应的 s 和 n 值。然后使用两个嵌套的循环来遍历每一个可能的 n 值，并计算对应的 s 值。在计算出新的 s 值后，使用 abs 函数计算出与 8 的差值的绝对值，并与当前的最小差值进行比较。如果当前的差值比最小差值还要小，则更新最小差值和对应的 s 和 n 值。最后输出最终的结果。

Answer 2

n = 1
s = 1.0
min_diff = abs(s - 8.0)
while True:
n += 1
s += 1.0 / n
diff = abs(s - 8.0)
if diff < min_diff:
min_diff = diff
closest_s = s
closest_n = n
if s >= 8.0:
break
print("与八最接近的s值为:", closest_s)
print("对应的n值为:", closest_n)

Answer 3

s = 0
n = 1
closest_s = 0
closest_n = 0
while n <= 100:
s += 1/n
if abs(s - 8) < abs(closest_s - 8):
closest_s = s
closest_n = n
n += 1
print("The closest value of s to 8 is", closest_s, "which corresponds to n =", closest_n)