Question

已知a+b=2,ab=2分之1,求二分之一a的三次方b+a平方b平方+二分之一ab的三次方

题目再次a³b/2+a²b²+ab³/2

Answer 1

原式=ab/2(a²+2ab+b²)
=ab/2(a+b)²
=1/2÷2×2²
=1

Answer 2

a³b/2+a²b²+ab³/2
=ab/2(a²+2ab+b²)
=ab/2(a+b)²
a+b=2
(a+b)²=2²=4
ab=1/2
ab/2=1/4
原式=ab/2(a+b)²
=1/4*4
=1

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Answer 3

a³b/2＋a²b²＋ab³/2
＝ab/2(a²＋2ab＋b²)
＝ab/2(a＋b)²
＝1/2/2×2²
＝1/4×4
＝1

Answer 4

a³b/2+a²b²+ab³/2
=ab(a²/2+ab+b²/2)
=ab(a²+2ab+b²)/2
=ab(a+b)²/2
=1/2 * 2² /2
=1