Question

(x^2-4/x^2-4x+4-x-2/x+2)÷x/x-2

Answer 1

收起
(x^2-4/x^2-4x+4-x-2/x+2)÷x/x-2
=((x+2)(x-2)/(x-2)²-(x-2)/(x+2))×(x-2)/x
=(x+2)/x-(x-2)/x
=4/x;

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Answer 2

原式=[(x+2)(x-2)/(x-2)^2-(x-2)/(x+2)]*(x-2)/x
=[(x+2)/(x-2)-(x-2)/(x+2)]*(x-2)/x
=[(x+2)^2-(x-2)^2]/(x-2)*(x+2)*(x-2)/x
=4x/(x+2)*1/x
=4/(x+2)