该页面为什么点击a标签会不能跳转 页面路径正确
<!DOCTYPEhtml><html><head><metacharset="utf-8"/><title></title></head><body><ahref="j...
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8" />
<title></title>
</head>
<body>
<a href="javascript:void(0)" onclick="open()">11111111</a>
<script src="学习/js/jquery-2.1.1.js"></script>
<script>
function open(){
var ss = window.open('study.html');
//window.location = 'study.html';
}
</script>
</body>
</html>
问题是因为采用了保留字open做函数名 展开
<html>
<head>
<meta charset="utf-8" />
<title></title>
</head>
<body>
<a href="javascript:void(0)" onclick="open()">11111111</a>
<script src="学习/js/jquery-2.1.1.js"></script>
<script>
function open(){
var ss = window.open('study.html');
//window.location = 'study.html';
}
</script>
</body>
</html>
问题是因为采用了保留字open做函数名 展开
1个回答
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因为方法没有执行,实例化没有。
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8" />
<title></title>
</head>
<body>
<a href="javascript:void(0)" onclick="open()">11111111</a>
<script src="学习/js/jquery-2.1.1.js"></script>
<script>
function open(){
var ss = window.open('study.html');
//window.location = 'study.html';
}
</script>
</body>
</html>
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8" />
<title></title>
</head>
<body>
<a href="javascript:void(0)" onclick="open()">11111111</a>
<script src="学习/js/jquery-2.1.1.js"></script>
<script>
function open(){
var ss = window.open('study.html');
//window.location = 'study.html';
}
</script>
</body>
</html>
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