Question

先化简，再求值，x²+2x+1除以x+2加上x²-1除以x-1减去x除以x+2，其中x=根号三-2

Answer 1

答：
原式
=(x²+2x+1)/(x+2)+(x²-1)/(x-1)-x/(x+2)
=(x²+2x+1-x)/(x+2)+(x-1)(x+1)/(x-1)
=(x²+x+1)/(x+2)+x+1
=(x²+x+1+x²+3x+2)/(x+2)
=(2x²+4x+3)/(x+2)
=2x+3/(x+2)
=2*(√3-2)+3/(√3-2+2)
=2√3-4+√3
=3√3-4