Question

题如下：7500×(1+4.5%)³º＝?和7500×(1+4.5%)²º＝? 分别是多少?

Answer 1

Splitsthisstringaroundmatchesofthegivenregularexpression.Thearrayreturnedbythismethodcontainseachsubstringofthisstringthatisterminatedbyanothersubstringthatmatchesthegivenexpressionoristerminatedbytheendofthestring.Thesubstringsinthearrayareintheorderinwhichtheyoccurinthisstring.Iftheexpressiondoesnotmatchanypartoftheinputthentheresultingarrayhasjustoneelement,namelythisstring.Thelimitparametercontrolsthenumberoftimesthepatternisappliedandthereforeaffectsthelengthoftheresultingarray.Ifthelimitnisgreaterthanzerothenthepatternwillbeappliedatmostn-1times,thearray'slengthwillbenogreaterthann,andthearray'slastentrywillcontainallinputbeyondthelastmatcheddelimiter.Ifnisnon-positivethenthepatternwillbeappliedasmanytimesaspossibleandthearraycanhaveanylength.Ifniszerothenthepatternwillbeappliedasmanytimesaspossible,thearraycanhaveanylength,andtrailingemptystringswillbediscarded.Thestring"boo:and:foo",forexample,yieldsthefollowingresultswiththeseparameters:RegexLimitResult:2{"boo","and:foo"}:5{"boo","and","foo"}:-2{"boo","and","foo"}o5{"b","",":and:f","",""}o-2{"b","",":and:f","",""}o0{"b","",":and:f"}Aninvocationofthismethodoftheformstr.split(regex,n)yieldsthesameresultastheexpressionjava.util.regex.Pattern.compile(regex).split(str,n)Parameters:regexthedelimitingregularexpressionlimittheresultthreshold,asdescribedaboveReturns:thearrayofstringscomputedbysplittingthisstringaroundmatchesofthegivenregularexpressionThrows:PatternSyntaxException-iftheregularexpression'ssyntaxisinvalidSince:1.4SeeAlso:java.util.regex.Pattern@specJSR-51以上是jdk的注解，参数-1表示split次数没有限制，

Answer 2

7500×(1+4.5%)³º＝28089.8860090265
7500×(1+4.5%)²º＝18087.8551862805