Question

(2又2/9+3又4/7+1又4/11)除以(3/11+5/7+4/9)

(2又2/9+3又4/7+1又4/11)除以(3/11+5/7+4/9)

Answer 1

（2又2/9+3又4/7+1又4/11）除以（3/11+5/7+4/9）
=（3/11+5/7+4/9）/（20/9+25/7+26/11）
=（189/693+495/693+308/693）x（1540/693+2475/693+1638/693）
=（992/693）/（5653/693）
=992/5653

Answer 2

(2又2/9+3又4/7+1又4/11)÷(3/11+5/7+4/9)
=（2+3+1+154/693+396/693+252/693）÷(189/693+495/693+308/693)
=(6+802/693)÷(992/693)
=(6x693+802)÷992
=4960/992
=5