
VB:使用数组结构编写一个程序,输入10个学生的成绩,统计最高分、最低分和平均分
要求:单击command4按钮,用inputbox()函数输入10个成绩数据,并在picture1图形框中显示所输入的成绩:单击command1按钮,在text1文本框中...
要求:单击command4按钮,用inputbox()函数输入10个成绩数据,并在picture1图形框中显示所输入的成绩:单击command1按钮,在text1文本框中显示最高分;单击command2按钮,在text2文本框中显示最低分;单击command3按钮,在text3文本框中显示平均分
各位高手帮帮忙吧,谢谢啦! 展开
各位高手帮帮忙吧,谢谢啦! 展开
1个回答
展开全部
Option Explicit
Dim sdt(1 To 10) As Double
Private Sub Command1_Click()
Dim i As Integer, max As Double
max = sdt(1)
For i = 1 To 10
If sdt(i) > max Then
max = sdt(i)
End If
Next i
Text1.Text = Str(max)
End Sub
Private Sub Command2_Click()
Dim i As Integer, min As Double
min = sdt(1)
For i = 1 To 10
If sdt(i) < min Then
min = sdt(i)
End If
Next i
Text2.Text = Str(min)
End Sub
Private Sub Command3_Click()
Dim i As Integer, aver As Double
For i = 1 To 10
aver = aver + sdt(i)
Next i
aver = aver / 10
Text3.Text = Str(aver)
End Sub
Private Sub Command4_Click()
Dim i As Integer
For i = 1 To 10
sdt(i) = InputBox("input sdt(i) grade")
Next i
For i = 1 To 10
Picture1.Print sdt(i)
Next i
End Sub
Dim sdt(1 To 10) As Double
Private Sub Command1_Click()
Dim i As Integer, max As Double
max = sdt(1)
For i = 1 To 10
If sdt(i) > max Then
max = sdt(i)
End If
Next i
Text1.Text = Str(max)
End Sub
Private Sub Command2_Click()
Dim i As Integer, min As Double
min = sdt(1)
For i = 1 To 10
If sdt(i) < min Then
min = sdt(i)
End If
Next i
Text2.Text = Str(min)
End Sub
Private Sub Command3_Click()
Dim i As Integer, aver As Double
For i = 1 To 10
aver = aver + sdt(i)
Next i
aver = aver / 10
Text3.Text = Str(aver)
End Sub
Private Sub Command4_Click()
Dim i As Integer
For i = 1 To 10
sdt(i) = InputBox("input sdt(i) grade")
Next i
For i = 1 To 10
Picture1.Print sdt(i)
Next i
End Sub
本回答被提问者采纳
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询