Question

json字符串怎么转化为list

Answer 1

import java.util.HashMap;
import java.util.Map;
import net.sf.json.JSONObject;
public class Test {
public static void main(String[] args) {
String json = "{\"name\":\"reiz\"}";
JSONObject jsonObj = JSONObject.fromObject(json);
String name = jsonObj.getString("name");

jsonObj.put("initial", name.substring(0, 1).toUpperCase());
String[] likes = new String[] { "JavaScript", "Skiing", "Apple Pie" };
jsonObj.put("likes", likes);
Map <String, String> ingredients = new HashMap <String, String>();
ingredients.put("apples", "3kg");
ingredients.put("sugar", "1kg");
ingredients.put("pastry", "2.4kg");
ingredients.put("bestEaten", "outdoors");
jsonObj.put("ingredients",ingredients);

System.out.println(jsonObj);
}
}
//这是使用org.json的程序：
import java.util.HashMap;
import java.util.Map;
import org.json.JSONException;
import org.json.JSONObject;
public class Test {
public static void main(String[] args) throws JSONException {
String json = "{\"name\":\"reiz\"}";
JSONObject jsonObj = new JSONObject(json);
String name = jsonObj.getString("name");
jsonObj.put("initial", name.substring(0, 1).toUpperCase());
String[] likes = new String[] { "JavaScript", "Skiing", "Apple Pie" };
jsonObj.put("likes", likes);
Map <String, String> ingredients = new HashMap <String, String>();
ingredients.put("apples", "3kg");
ingredients.put("sugar", "1kg");
ingredients.put("pastry", "2.4kg");
ingredients.put("bestEaten", "outdoors");
jsonObj.put("ingredients", ingredients);
System.out.println(jsonObj);
System.out.println(jsonObj);
}
}
//两者的使用几乎是相同的，但org.json比json-lib要轻量得多，前者没有任何依赖，而后者要依赖ezmorph和commons的lang、logging、beanutils、collections等//组件。