三角函数推导写出详细步骤
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2017-08-03 · 知道合伙人教育行家
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sin(a+b)-sina
=sin[(2a+b)/2+b/2]-sin[(2a+b)/2-b/2]
=sin(2a+b)/2 cosb/2+cos(2a+b)/2 sinb/2
-[sin(2a+b)/2 cosb/2-cos(2a+b)/2 sinb/2]
=sin(2a+b)/2 cosb/2+cos(2a+b)/2 sinb/2
-sin(2a+b)/2 cosb/2+cos(2a+b)/2 sinb/2
=2cos(2a+b)/2 sinb/2
=2cos(a+b/2)sinb/2
=sin[(2a+b)/2+b/2]-sin[(2a+b)/2-b/2]
=sin(2a+b)/2 cosb/2+cos(2a+b)/2 sinb/2
-[sin(2a+b)/2 cosb/2-cos(2a+b)/2 sinb/2]
=sin(2a+b)/2 cosb/2+cos(2a+b)/2 sinb/2
-sin(2a+b)/2 cosb/2+cos(2a+b)/2 sinb/2
=2cos(2a+b)/2 sinb/2
=2cos(a+b/2)sinb/2
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