Question

c语言设计万年历 输入任意年份，输出该年12个月份 输入任意年份月份，输出该年月日历

Answer 1

程序直接输入年份和月份，打印对应日历。

一年12个月是固定的，我就不写单独输入年份打印月份了。你想就把我月份数组打印一遍好了。

#include<stdio.h>
#include<time.h>
#include<malloc.h>
enum MONTH{January=1,February,March,April,May,June,July,August,September,October,November,December};
struct tm * getDate(int year,int mon);
void printTime(time_t theTime,int year);
int main()
{
    enum MONTH mon;
    time_t theTime;
    struct tm *date;
    int year,m;
    while(1)
    {
        printf("输入任意年份及月份：\n");
        scanf("%d%d",&year,&m);
        if(m<1 || m>12)
        {
            printf("月份超出范围，重新输入！\n");
            continue;
        }
        mon=m;
        break;
    }
    date=getDate(year,mon);
    theTime=mktime(date);//从1900年至此的秒数
    printTime(theTime,year);
    return 0;
}
struct tm * getDate(int year,int mon)
{
    struct tm *date=(struct tm *)malloc(sizeof(struct tm));
    date->tm_sec=0;
    date->tm_min=0;
    date->tm_hour=0;
    date->tm_year=year-1900;
    date->tm_mon=mon-1;
    date->tm_mday=1;
    date->tm_yday=0;
    return date;
};
void printTime(time_t theTime,int year)
{
    int y,m,wday,i,j;
    char wd[7][7]={"星期日","星期一","星期二","星期三","星期四","星期五","星期六"};
    struct tm *date;
    date =localtime(&theTime);
    y=date->tm_year+1900;
    m=date->tm_mon+1;
    wday=date->tm_wday;
    printf("\n------------------开始生成日历----------------------\n\n");
    printf("                   %d年%02d月\n",y,m);
    i=0;
    for(j=0;j<7;j++)
    {
        printf("%s ",wd[wday++]);
        if(wday>6)
            wday=0;
    }
    printf("\n");
    while(1)
    {
        if(date->tm_mon+1>m)
        {
            printf("\n");
            break;
        }
        printf(" %02d日  ",date->tm_mday);
        if(++i==7)
        {
            printf("\n");
            i=0;
        }
        theTime+=24*60*60;
        date =localtime(&theTime);
    }
}

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为啥我复制你的显示有错误呢？

为啥我复制你的显示有错误呢？