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请各位大佬帮忙解决一下分析化学题目,谢谢各位了!!!
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解,体积乘以mol浓度得到物质的量再乘以分子量就是草酸的质量.
0.1mol/L*.05L*126=0.6300g=630mg
0mol酸与2mol碱中和.
碱的量=0.1025*0.02305=0.00236
酸的mol浓度=0.00236/2=0.00118mol/L.
25ml中草酸的质量=0.025*0.00118*90.04=0.00277g=2.7736mg
0.1mol/L*.05L*126=0.6300g=630mg
0mol酸与2mol碱中和.
碱的量=0.1025*0.02305=0.00236
酸的mol浓度=0.00236/2=0.00118mol/L.
25ml中草酸的质量=0.025*0.00118*90.04=0.00277g=2.7736mg
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