Question

用python把列数据改为行数据,并用逗号隔开

198
1989
266
.....
转换成198,1989,266,.......

Answer 1

f = open('test.txt', 'r')                   #以读方式打开文件  
result = list()  
for line in f.readlines():                          #依次读取每行  
    line = line.strip()                             #去掉每行头尾空白  
    if not len(line) or line.startswith('#'):       #判断是否是空行或注释行  
        continue                                    #是的话，跳过不处理  
    result.append(line)                             #保存  

print ','.join(result)

Answer 2

colfile=open(r'cols.txt')
rowfile=open(r'rows.txt','w')
rowlist=[]
for line in colfile.readlines():
    collist=line.split()
    index=0
    for col in collist:
        try:
            rowlist[index].append(col)
        except IndexError:
            rowlist.append([col])
        index=index+1

for row in rowlist:
    rowfile.write(','.join(row))
    rowfile.write('\n')

colfile.close()
rowfile.close()

以上代码打开列数据文件cols.txt,然后转换为行数据写入文件rows.txt

追问

谢谢您

Answer 3

open('dst.txt', 'w').write(open('src.txt','r').read().replace('\n',','))

追问

open(r'dst.txt', 'w').write(open(r'src.txt','r').read().replace('\n',','))

谢谢您