(6x-1)(2x-1)(3x-1)(x-1)+x�0�5 因式分解
2个回答
2013-07-08
展开全部
(6x-1)(2x-1)(3x-1)(x-1)+x^2=(6x^2-7x+1)(6x^2-5x+1)+x^2=[(6x^2+1)-7x][(6x^2+1)-5x]+x^2=(6x^2+1)^2-12x(6x^2+1)+36x^2=(6x^2+1-6x)^2
2013-07-08
展开全部
(6x-1)(2x-1)(3x-1)(x-1)+x�0�5
=[(2x-1)(3x-1)][(6x-1)(x-1)]+x�0�5
=(6x�0�5-5x+1)(6x�0�5-7x+1)+x�0�5
=[(6x�0�5-6x+1)+x][(6x�0�5-6x+1)-x]+x�0�5
=(6x�0�5-6x+1)�0�5-x�0�5+x�0�5
=(6x�0�5-6x+1)�0�5
=[(2x-1)(3x-1)][(6x-1)(x-1)]+x�0�5
=(6x�0�5-5x+1)(6x�0�5-7x+1)+x�0�5
=[(6x�0�5-6x+1)+x][(6x�0�5-6x+1)-x]+x�0�5
=(6x�0�5-6x+1)�0�5-x�0�5+x�0�5
=(6x�0�5-6x+1)�0�5
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