Question

求ASP 文章上一篇、下一篇翻页功能代码、

Answer 1

具体要根据你的SQL分类条件来设定
假设没有任何设定,就是显示全部文章,按ID升序来排序
假设id为当前文章的ID
下一篇就是:
"select top 1 * from 表 where id>" & id & " order by id "
上一篇就是:
"select top 1 * from 表 where id<" & id & " order by id desc"

Answer 2

%>
rs.pagesize=4
if request("page")<>"" then
epage=cint(request("page"))
if epage<1 then epage=1
if epage>rs.pagecount then epage=rs.pagecount
else
epage=1
end if
rs.absolutepage=epage
%>
~~~~~~~~~~~~~~~~~~~~
<%
for i=0 to rs.pagesize-1
if rs.bof or rs.eof then exit for
%>

<p align="center">
<a href="">首页</a>
<a href="chakan.asp?page=<%=epage-1%>">前一页</a>
<a href="chakan.asp?page=<%=epage+1%>">后一页</a>
<a href="chaka.asp?page=<%=rs.pagecount%>">末页</a>
<p></p>
<p align="center">现在是第<%=epage%>页一共有<%=rs.pagecount%>页</p>