请懂这题数学题的朋友，可以帮我解答图片中的答案，需要详细公式，可以写好照个相片回复我就可以了谢谢！
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第二题 只要求倒数就行了
y^2+3y-1=0
y+3-1/y=0
y-1/y=-3
y^4-3+1/y^4
=(y^2-1/y^2)^2-1
=(y-1/y)^2(y+1/y)^2-1
=9(y^2+2+1/y^2)-1
=9[(y-1/y)^2+4]-1
=9(9+4)-1
=116
原式=1/116
y^2+3y-1=0
y+3-1/y=0
y-1/y=-3
y^4-3+1/y^4
=(y^2-1/y^2)^2-1
=(y-1/y)^2(y+1/y)^2-1
=9(y^2+2+1/y^2)-1
=9[(y-1/y)^2+4]-1
=9(9+4)-1
=116
原式=1/116
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