Question

定义一个字符串,定义一个字节数组.

输入字符串:spread Chinese Culture,Chinese Culture,Guide to Chinese Culture
求Culture最后一个的位置，小写字符转换成大写后的新串
字符串转成字节数组后倒序输出
请大家帮帮忙：
定义一个字符串，定义一个字节数组。
spread Chinese Culture,Chinese Culture,Guide to Chinese Culture
要求1)输出：该字符串，该字符串中单词个数，“Culture”的个数，最后一个”Culture”出现的位置，小写字符转换成大写后的新串
2)字符串转成字节数组后倒序输出

Answer 1

编程内容如下：
String str = "spread Chinese Culture,Chinese Culture,Guide to Chinese Culture";
str = str.trim();
System.out.println("原字符串是:"+str);
System.out.println("最后一个Culture出现的位置是:"+str.lastIndexOf("Culture"));
System.out.println("小写转换成大写字符后:"+str.toUpperCase());

int count = 0;
int cul = 0;
System.out.print("转换为数组且倒序输出后:");
byte[] b = str.getBytes();
for (int i = b.length-1; i >= 0; i--) {
System.out.print((char)b[i]);
if(String.valueOf((char)b[i]).equals(" ") || String.valueOf((char)b[i]).equals(",")){
count++;
}
if(str.indexOf("Culture") != -1){
cul++;
str = str.substring(str.indexOf("Culture")+7);
}
}
System.out.println();
System.out.println("字符串中单词总共个数是:"+(count+1));
System.out.println("Culture出现的次数是:"+cul);

Answer 2

1 不断用String.indexOf() 只转大写，String.toUpperCase()

2 String.getBytes()，然后数组从大到小

Answer 3

意思一下:
String str = "spread Chinese Culture,Chinese Culture,Guide to Chinese Culture";
str = str.trim();
System.out.println("原字符串是:"+str);
System.out.println("最后一个Culture出现的位置是:"+str.lastIndexOf("Culture"));
System.out.println("小写转换成大写字符后:"+str.toUpperCase());

int count = 0;
int cul = 0;
System.out.print("转换为数组且倒序输出后:");
byte[] b = str.getBytes();
for (int i = b.length-1; i >= 0; i--) {
System.out.print((char)b[i]);
if(String.valueOf((char)b[i]).equals(" ") || String.valueOf((char)b[i]).equals(",")){
count++;
}
if(str.indexOf("Culture") != -1){
cul++;
str = str.substring(str.indexOf("Culture")+7);
}
}
System.out.println();
System.out.println("字符串中单词总共个数是:"+(count+1));
System.out.println("Culture出现的次数是:"+cul);