Question

化简，再求值，X分之X+1除（X-2X分之1+X的平方）,其中X=根号2+1

过程怎么算了,给我说说

Answer 1

(x+1)/x ÷ [x -(x²+1)/2x]
= (x+1)/x ÷ [2x² -(x²+1)]/2x
=(x+1)/x ÷ (x²-1)/2x
=(x+1)/x × 2x/(x+1)(x-1)
=2/(x-1)
将x=√2 +1代入上式
原式=2/(√2+1-1)
=√2

Answer 2

(x+1)/x ÷ [x -(x+1)/2x]= (x+1)/x ÷ [(2x�0�5 -x-1)/2x]=(x+1)/x ÷ [(2x+1)(x-1)/2x]=(x+1)/x × [2x/(2x+1)(x-1)]=2(x+1)/(2x+1)(x-1)将x=√2 +1代入上式原式=2(√2 +2)/[(2√2 +3)×√2 ] =(2+2√2 )/(3 -2√2 ) =2√2 -2

Answer 3

方程你是杂学的啊 等回家了我教你 真佩服你

Answer 4

你真叼