Question

VB6.0中MSFlexGrid控件的用法

(Microsoft FlexGrid Control 6.0)控件在VB6.0中如何用它来操纵数据库,主要是使用它来显示/修改Access数据库的字段和记录以及它的一些基本属性或者主要的属性的用法,能有例题说明最好...

Answer 1

★呵呵！

>> 将文本赋值给MsFlexGrid的单元格
MsFlexGrid.TextMatrix(3,1)=”Hello”

>> 在MsFlexGrid控件单元格中插入背景图形
Set MsFlexGrid.CellPicture=LoadPicture(“C:\temp\1.bmp”)

>>选中某个单元
MsFlexGrid.Row=1
MsFlexGrid.Col=1

>>用粗体格式化当前选中单元
MsFlexGrid.CellFontBold=True

>> 添加新的一行
使用AddItem方法,用Tab字符分开不同单元格的内容
dim row as string
row=”AAA”&vbtab&”bbb”
MsFlexFrid1.addItem row

>>怎样来实现MSFlexGrid控件单数行背景为白色，双数的行背景为蓝色?
Dim i As Integer
With MSFlexGrid1
.AllowBigSelection = True ’ 设置网格样式
.FillStyle = flexFillRepeat
For i = 0 To .Rows - 1
.Row = i: .Col = .FixedCols
.ColSel = .Cols() - .FixedCols - 1
If i Mod 2 = 0 Then
.CellBackColor = &HC0C0C0 ’ 浅灰
Else
.CellBackColor = vbBlue ’ 兰色
End If
Next i
End With

>> MSFlexGrid控件如何移到最后一行
MSFlexGrid1.TopRow = MSFlexGrid1.Rows – 1

>>如何判断msflexgrid有无滚动条
Declare Function GetScrollRange Lib "user32" (ByVal hWnd As Long, ByVal nBar As Long, lpMinPos As Long, lpMaxPos As Long) As Long
Public Const SB_HORZ = &H0
Public Const SB_VERT = &H1

Public Function VsScroll(MshGrid As MSHFlexGrid) As Boolean ’判断水平滚动条的可见性
Dim i As Long
VsScroll = False
i = GetScrollRange(MshGrid.hWnd, SB_HORZ, lpMinPos, lpMaxPos)
If lpMaxPos <> lpMinPos Then VsScroll = True
End Function

Public Function HeScroll(MshGrid As MSHFlexGrid) As Boolean ’判断垂直滚动条的可见性
Dim i As Long
HeScroll = False
i = GetScrollRange(MshGrid.hWnd, SB_VERT, lpMinPos, lpMaxPos)
If lpMaxPos <> lpMinPos Then HeScroll = True
End Function

>>程序运行时，想动态增加MSFlexgrid的列数
在第2列后插入一列：
Private Sub Form_Load()
Me.MSHFlexGrid1.Cols = 5
MSHFlexGrid1.Rows = 2
For i = 0 To Me.MSHFlexGrid1.Cols - 1
Me.MSHFlexGrid1.TextMatrix(0, i) = i
Me.MSHFlexGrid1.TextMatrix(1, i) = i
Next
End Sub

Private Sub Command1_Click()
Me.MSHFlexGrid1.Cols = Me.MSHFlexGrid1.Cols + 1
Me.MSHFlexGrid1.ColPosition(5) = 3
End Sub

>> 请教MSFlexGrid中的对齐功能的使用
设置MSFlexGrid1.ColAlignment(index)=n

>>得到MSFlexGrid控件中当前选中的一行
msflexgrid1.rowsel就是当前选中行

>> 如何通过代码调节列宽度
msflexgrid1.colwidth(i)=4000