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第一题求解!
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解:∵由a2-a-1=0两边同时除以a得,a-a-1=1,
进而a2+a-2=3,a4+a-4=7,
∴a8+7a-4,
=a4(a4+a-4)+7a-4-1,
=7a4+7a-4-1,
=7(a4+a-4)-1,
=48.
进而a2+a-2=3,a4+a-4=7,
∴a8+7a-4,
=a4(a4+a-4)+7a-4-1,
=7a4+7a-4-1,
=7(a4+a-4)-1,
=48.
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