x-1分之一+(x-1)(x-2)分之一+(x-2)(x-3)分之一+(x-3)(x-4)分之一+(x-4)+(x-5)分之一
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2013-07-16
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1/(x-1)+1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4)+1/(x-4)(x-5)=[(x-2)+1]/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4)+1/(x-4)(x-5)=1/(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4)+1/(x-4)(x-5)=[(x-3)+1]/(x-2)(x-3)+1/(x-3)(x-4)+1/(x-4)(x-5)=1/(x-3)+1/(x-3)(x-4)+1/(x-4)(x-5)=1/(x-4)+1/(x-4)(x-5)=1/(x-5)
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